A small steel ball falls through a syrup at constant speed of 10 cm/s. If the steel ball is pulled upwards with a force equal to twice its effective weight, how fast will it move upwards?
Text Solution
Verified by ExpertsThe correct answer is:
A
mg – F V – F up = ma = 0
mg = F V + F up ... (i)
Now
F– mg – F V – F up = 2mg – mg – F V – F up
= mg – F V – F up = 0
Acceleration in second case = 0
∴ ball will move upward with constant speed = 10 cm/s
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